li = [5,6,77,45,22, 2 ,12,35,57]
for i in li:
# print(i)
if (i%2 == 0):
print(i)
li.remove(i)
else:
pass
print(li)
why my output is coming this [5, 77, 45, 12] after writing above code
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Michael Szczesny
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AMARENDRA PANDEY
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2don't use `li.remove(i)` in a loop – juanpa.arrivillaga Jan 20 '22 at 18:01
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1Create a new list – DarkKnight Jan 20 '22 at 18:01
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append the odd numbers to a new list instead – stefan_aus_hannover Jan 20 '22 at 18:01
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4Deleting elements while iterating a `list` will skip the next element. – Michael Szczesny Jan 20 '22 at 18:02
1 Answers
1
append the odd numbers to a new list instead
li = [5,6,77,45,22, 2 ,12,35,57]
li2 = []
for i in li:
if (i%2 != 0):
print(i)
li2.append(i)
else:
pass
print(li2)
stefan_aus_hannover
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