print(3 in [1, 2, 3] == [1, 2, 3])
#Output: True
print((3 in [1, 2, 3]) == [1, 2, 3])
#Output: False
I'm just wondering what is happening here.
Asked
Active
Viewed 49 times
0
John Kugelman
- 349,597
- 67
- 533
- 578
Python learner
- 1,159
- 1
- 8
- 20
1 Answers
2
Because of Python's comparison chaining feature.
3 in [1, 2, 3] == [1, 2, 3]
is treated as
(3 in [1, 2, 3]) and ([1, 2, 3] == [1, 2, 3])
Barmar
- 741,623
- 53
- 500
- 612
-
1Are you familiar with `1 < variable < 10`? It's the same thing. – Barmar Jan 25 '22 at 17:33
-
Wait, what !? Isn't it same as `1 < variable and variable < 10` how you guys just do these things? That's really nice way to understand this concept. – Python learner Jan 25 '22 at 17:39
-
1Yes, it's the same as that. What's surprising is that `in` is considered similar to `<`. – Barmar Jan 25 '22 at 17:46