How to split the array if the Array.length is higher than 5 in javascript

Question

const array = [1...7]

so i have this array as u can see the length is 7, so i want the result like this

[1, 2, 3, 4, 5] and [6, 7]

same for the array below

const array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]

the length is 11, therefore the result i want should be

[1, 2, 3, 4, 5] and [7, 8, 9, 10] and [11]

why 11 only? because i want to seperate array lengths by 5

Where did 6 go in the second example? And what is the problem you have in doing what you describe? — trincot, Jan 31 '22 at 13:52

score -1 · Answer 1 · answered Jan 31 '22 at 14:02

I had written an splitter function that does the job:

const array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]

function splitter ( arr, length = 5 ) {
  let result = [];
  let intermediateArray = [];
  arr.reverse().map( (el,index) => {
    intermediateArray.push(el);
   
    if (index % length === 0) {
      result.push(intermediateArray.reverse());
      intermediateArray = []
    }
  })
  return result.reverse();
}

console.log(splitter(array))

How to split the array if the Array.length is higher than 5 in javascript

1 Answers1