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i defined Property. i modified a answer found here How do I undo a Object.defineProperty call?

Object.defineProperty(it, 'log', {  
  get() {  
    return console.log.bind(console, `[${Date.now()}]`, '');  
 },  
});
console.log(`line of this console log will follow next line`);

I don't need it anymore and have been trying to remove it for a while.

so i read here How do I undo a Object.defineProperty call?

and tried then to delete it like so

delete Object.prototype.log;
delete Object.prototype.it;

also tried to redefine it as was at the beginning:

Object.defineProperty(it, 'log', {
  get() {
    return console.log.bind(console, ``, '');
  },
});

with no effect.

and

Object.defineProperty(it, 'log', {
  value: "",
  writable: false
});

with no effect.

now i always see if i use a

console.log(msg);

below something with (src/script.js:28:11)

example results:

console.log('000000'); i get at Object.<anonymous> (src/script.js:28:11)

if i use console.log('000000', '111111');

console.log
    000000 111111

      at Object.<anonymous> (src/script.js:36:11)
SL5net
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1 Answers1

1

there is an example of how you can overwrite the object. If the object is not a 'const'

let object1 = {"test": 123};

Object.defineProperty(object1, 'property1', {
  value: 42,
  writable: false
});

object1.property1 = 77;

console.log(object1.property1); // 42

const {property1, ...rest} = object1
object1 = {...rest}
console.log(object1.property1) // undefinded
Kordrad
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  • now woked if i use it so ``` Object.defineProperty(it, 'log', { value: "", writable: false }); ``` – SL5net Feb 02 '22 at 09:32