Invalid argument error while opening file in python

Question

code:

f=open("C:\\Users\Dell\assignment1\random_walk_tenk.dat","r")

I got the error:

OSError: [Errno 22] Invalid argument: 'C:\\Users\\Dell\x07ssignment1\random_walk_tenk.dat'

In this line, what I am doing wrong?

Answer 1

Forward slashes needs to be escaped. Better way is to use raw string by suffixing string with r.

try:

with open(r"C:\\Users\Dell\assignment1\random_walk_tenk.dat") as f:
    data = f.read()

I do this insted.

from pathlib import Path

data = Path("C://Users/Dell/assignment1/random_walk_tenk.dat").read_text()

Answer 2

you can add r string it will fix it r""

f=open(r"C:\\Users\Dell\assignment1\random_walk_tenk.dat","r")