-1

Instead of 1 index on each row, I want horizontal not vertical returns.

let n = [6];

function staircase() {
  for (let i = 1; i <= n; i++) {
    for (let j = 1; j <= n - i; j++) {
      console.log("0");
    }
    for (let k = 1; k <= i; k++) {
      console.log('#');
    }

  }
}

staircase();

But I need it to render like this. (This works using Java; it's the same logic, but renders differently.)

     #
    ##
   ###
  ####
 #####
######
isherwood
  • 58,414
  • 16
  • 114
  • 157
Mr Green81
  • 1
  • this is from the staircase problem on hackerrank. i know how to use .repeat().padstart(). but i just want to get this code to work. – Mr Green81 Feb 04 '22 at 14:46
  • 2
    Please don't add new information in comments. There's an Edit button right there. See [ask] and take the [tour]. – isherwood Feb 04 '22 at 14:49
  • 2
    if you *'know how to use .repeat().padstart()'* then just make your loops do what those two methods do, namely pad the start of the string with a repeated substring. – pilchard Feb 04 '22 at 14:56
  • Thanks for the info – Mr Green81 Feb 04 '22 at 16:49

2 Answers2

1

console.log prints one line each therefore i put 2 variables to keep the empty string and hash string and after the loops logged the concatenation of the strings

let n = 6

function staircase() {
  for (let i = 1; i <= n; i++) {
    let emptyString = '';
    let hashString = '';
    for (let j = 1; j <= n - i; j++) {
      emptyString += " ";
    }
    for (let k = 1; k <= i; k++) {
      hashString += '#'
    }
    console.log(emptyString + hashString)

  }
}

staircase();
cmgchess
  • 7,996
  • 37
  • 44
  • 62
0

const n = [6] 
for (let i = 1; i <= n; i++) {
     //
    // this array stores the results; 
   //
    const array = [];
  //
    for (let j = 1; j <= n - i; j++) {
      array.push("0");
    }
    for (let k = 1; k <= i; k++) {
      array.push('#');
    }
    // adding `toString`, does the magic
    console.log(array.toString())
}
Christopher
  • 27
  • 4