Can I count identical tuples of strings in my list?

Question

I have generated a list of tuples from a separate code to show which pairs of numbers converge (in certain equations) given different combinations of variables. I need a way to count how many of each sequence or tuple there are here in my list. Because of the way I generated the variables to begin with, the tuples are strings.

If ('1','3') is in the list 8 times, I would want to be able to return ('1''3') and the count.

converge_list=[('1', '3'), ('1', '7'), ('2', '6'), ('3', '5'), ('7', '9'), ('1', '3'), ('1', '7'), ('2', '6'), ('3', '5'), ('7', '9'), ('1', '3'), ('1', '7'), ('1', '9'), ('2', '6'), ('3', '9'), ('5', '9'), ('1', '3'), ('1', '7'), ('2', '6'), ('3', '5'), ('7', '9'), ('1', '3'), ('1', '5'), ('1', '7'), ('2', '6'), ('3', '5'), ('3', '9'), ('1', '3'), ('1', '7'), ('1', '9'), ('2', '6'), ('3', '9'), ('5', '9'), ('1', '3'), ('1', '7'), ('2', '6'), ('3', '7'), ('1', '3'), ('1', '7'), ('2', '6'), ('3', '5'), ('3', '9'), ('7', '9'), ('1', '3'), ('1', '7'), ('1', '9'), ('2', '6'), ('3', '5'), ('3', '9'), ('7', '9'), ('1', '3'), ('1', '5'), ('1', '7'), ('2', '6'), ('3', '5'), ('3', '9')]

score 1 · Accepted Answer · answered Feb 06 '22 at 20:47

1

Probably not the most efficient solution.

for element in set(converge_list):
    print(element, converge_list.count(element))

answered Feb 06 '22 at 20:47

mwo

446
3
9

thank you, I don't have enough rep points to upvote, but this is exactly what I needed! – mickey_._._ Feb 06 '22 at 20:50

score -2 · Answer 2 · answered Feb 06 '22 at 20:40

-2

You can convert the tuples to strings by str(tuple) function and count each of them using dictionary.

answered Feb 06 '22 at 20:40

asgarov

41
6

1

Please read [answer] and try to answer questions directly. – Karl Knechtel Feb 06 '22 at 20:53

Can I count identical tuples of strings in my list?

2 Answers2