Web Scraping: How to click a specific href link in selenium python?

Question

I wanted to automate a web page using webdriver(Python) wherein the script will click on the href link directly in order to navigate to other page. Couple of details in the specific tag:

<span class = "xyz", ui-sref ="abc", href= "/letters/letters_number/"> 
"hdf"
<i class = 'icons'>letters</i>
</span>

Thanks, Gaj. But what I have mentioned in the description above, the tag details, I couldn't find a great match. Hence, would need someone's help. — , Feb 08 '22 at 17:09
click the link like you would normally see how the URL looks and append that href to the base URL and then call your webdriver driver.get() to get that page — Andrew Ryan, Feb 08 '22 at 17:24

score 0 · Answer 1 · answered Feb 08 '22 at 17:48

To click() on a the element with the href attribute you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:

Using CSS_SELECTOR:

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "span[href=/letters/letters_number/] i.icons"))).click()

Using XPATH:

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//span[@href='/letters/letters_number/']//i[@class='icons']"))).click()

Note: You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Web Scraping: How to click a specific href link in selenium python?

1 Answers1