Since template functions cannot be virtual. Does anyone know how I would have Base::funcB() call *::funcA() depending on which class the object is from? See the third last line below.
class Base {
public:
template<typename T>
void funcA(const T& t){
std::cout<< "In Base with T = " << t << std::endl;
}
template<typename T>
void funcB(const T& t){
funcA(t);
}
};
class Derived: public Base {
public:
template<typename T>
void funcA(const T& t){
std::cout<< "In Derived with T = " << t << std::endl;
}
};
int main()
{
std::cout<<"Direct function override\n";
Base().funcA("ABC"); // Output: In Base with T = ABC
Derived().funcA("ABC"); // Output: In Derived with T = ABC
std::cout<<"\n\n";
std::cout<<"Indirect function invocation\n";
Base().funcB("ABC"); // Output: In Base with T = ABC
Derived().funcB("ABC"); // Output: In Base with T = ABC !!!BAD!!! I want Derived, not Based
return 0;
}
