How do i call this function inside the same function in python

Asked Feb 10 '22 at 15:40

Active Feb 10 '22 at 15:40

Viewed 11 times

I am making a game where you are lost in the forest, i made a function where it will ask a user for a number of what to do. I want to make it where if the number is not in the list it will make them enter it again and say what they entered is an invalid number. Instead it just shows up with invalid number and then it will stay there until enter is pressed. This is the code that i tried:

def askbear1():
print('WHAT DO YOU DO!')
print('1. See if I can find the bear')
print('2. Just ignore it')
print('3. Gather Materials to protect yourself')
bear1 = input('\nChoice: ')
time.sleep(1.5)
if bear1 == '1':
    input('You chose to try to find the bear')
elif bear1 == '2':
    input('You chose to ignore it')
elif bear1 == '3':
    input('You chose to gather materials to protect yourself')
else:
    input('Please enter a valid number')
    askbear1()

asked Feb 10 '22 at 15:40

blvuxe

You'd want to have a loop: `while True: inp = input(); if inp in valid_inputs break;` (in pseudocode) – Jack Deeth Feb 10 '22 at 15:43
1

And don't use `input` in place of a print statement. – matszwecja Feb 10 '22 at 15:44
@matszwecja OH I DIDNT NOTICE THAT, Thanks for identifying my bug – blvuxe Feb 10 '22 at 15:46
1

Anyway, using `while` loop instead of recursion as suggested in a duplicate q is a better choice as it does not put unnecessary strain on the stack. – matszwecja Feb 10 '22 at 15:51

How do i call this function inside the same function in python

0 Answers0