Why this switch statement works that way?

Asked Feb 12 '22 at 16:10

Active Feb 12 '22 at 16:10

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I got this question in C++ interview for the intership. I was really confused and still don't understand why it is working like that. The question was about output of the code below. Right output is 10, but my guess was 1. Can somebody explain this code?

 int a = 1;
    switch(a)
    {
        case 0:
            do{
                case 1:
                a++;
            }while(a < 10);
        break;
    }

asked Feb 12 '22 at 16:10

WashingtonD

Can you explain why you expect `1`? – HolyBlackCat Feb 12 '22 at 16:12
@HolyBlackCat I thought like that because "case 1" located inside of the "case 0". "Case 0" is not opened so "case 1" is kinda unreachable. – WashingtonD Feb 12 '22 at 16:18
Jumping into a loop is legal in C and in C++. [Related answer](https://stackoverflow.com/a/2921461/10871073) – Adrian Mole Feb 12 '22 at 16:21
1

Nah, it jumps straight to `case 1:`. It doesn't matter that it's nested in braces. – HolyBlackCat Feb 12 '22 at 16:24
http://blog.robertelder.org/switch-statements-statement-expressions/ (it is written for C, but most of it applies to C++, too) – Remy Lebeau Feb 12 '22 at 16:38

Why this switch statement works that way?

0 Answers0