Reading a txt file into a list without newlines in python

Question

I have a txt file that looks like this:

FSDAF  
HKLWF  
AAKEP

How can I read that into a list so it looks like this: lst = ['FSDAF', 'HKLWF', 'AAKEP']
I did something like this but I cant get rid of the newlines:

file = open('dane.txt', 'r')
lst = file.readlines()

And it displays the newlines like this:

['FSDAF\n', 'HKLWF\n', 'AAKEP\n']

with open("dane.txt", "r") as fp: data = [line.rstrip() for line in fp]; print(data) — Saeed Zahedian Abroodi, Feb 13 '22 at 20:51

score 2 · Accepted Answer · answered Feb 13 '22 at 20:10

2

You can use .rstrip():

data = ['FSDAF\n', 'HKLWF\n', 'AAKEP\n']
print([line.rstrip() for line in data])

answered Feb 13 '22 at 20:10

BrokenBenchmark

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@low_ratio, actually this is a better answer. +1 – FLAK-ZOSO Feb 13 '22 at 20:11
rstrip() removes all tailing blank space. Better solution is rstrip('\n') – Gerhard Powell Jan 21 '23 at 12:49

score 2 · Answer 2 · answered Feb 13 '22 at 20:11

2

You can open it...

with open('dane.txt', 'r') as file:
    ...

...then (into the with/as block) read the file...

content = file.read()

...then split it into a list:

myList = content.split('\n')

answered Feb 13 '22 at 20:11

FLAK-ZOSO

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Reading a txt file into a list without newlines in python

2 Answers2