i cannot understand why i get string when use * and list when not in python

Question

In Python i am creating a classmethod and i am using a classmethod to get my parameters from a string by spliting it i am getting what i want but cannot understand why i get a list when i am not using * and not getting list when using *. here's my code below.

 @classmethod
 def from_one_str(cls, onestr):
    print(*onestr.split(",")) # getting two string

 # on running this is result - John C++

    print(onestr.split(",")) # getting a list of two strings
 # on running this is result - ['John', 'C++']

 # This is what i am running - John = Programmer.from_one_str("John,C++")

Have you attempted to find out what the `*` is for? Why are you using it? — SiHa, Feb 16 '22 at 08:19

AKX · Answer 1 · 2022-02-16T08:25:08.280

2

In a function call, the * operator unpacks the given list into separate arguments.

print(*["John", "C++"])

is thus equivalent to

print("John", "C++")

To bring this back to your code:

def from_one_str(onestr):
    print(*onestr.split(","))

You call from_one_str() with the string "John,C++"
The string will be split by "John,C++".split(",") into ["John", "C++"]
That list will be then spread to arguments for print by the * operator.
print prints each argument – "John" and "C++" – separated by space.
You see John C++.

edited Feb 16 '22 at 08:25

answered Feb 16 '22 at 08:18

AKX

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ok it means * will convert that list in a tupple isn't it – Fgr Reloaded Feb 16 '22 at 08:22
No, that's not it. Read the linked documentation. – AKX Feb 16 '22 at 08:22
@FgrReloaded You confuse how * (and ** for that matter) works for function parameters (e.g. `def spam(*args, **kwargs):` and what it does in function calls e.g. `spam(*some_args)`. – buran Feb 16 '22 at 08:23
I got it thanks man – Fgr Reloaded Feb 16 '22 at 08:27

i cannot understand why i get string when use * and list when not in python

1 Answers1