Python function that turns a number into binary

Question

I know that in python there are certain functions like bin that turn decimal numbers into binary numbers. I would like to build one myself. I have tried the following:

def binary(n):
    bina = ''
    B = []
    if n == 0:
        bina = '0'
    else: 
        while n>0:
            x = 0
            while 2**x<n:
                x = x+1
                B.append(x-1)
                n = n-2**(x-1)

The problem is that when I have the exponents with base 2 in the array B I don’t know how to actually read them so that I obtain the actual binary number made of ones and zeroes. How can I make the code above work?

before someone says that my question was already asked, my question is how can I make the code above work,I know that there are other methods to make a binary convertion in python, but I would like to know what's wrong with mine and possibly make my code work.

https://www.instructables.com/How-to-Convert-Numbers-to-Binary/ — omercotkd, Feb 16 '22 at 13:50
@omercotkd I know that, but how I can implement it into my code was my question — Emilio, Feb 16 '22 at 13:52
@MichaelSzczesny Kind of, isn’t there a way to simply use the code I have published and get the binary by reading array `B`? — Emilio, Feb 16 '22 at 13:53

score 0 · Accepted Answer · answered Feb 16 '22 at 13:54

0

def make_binary(num):
    binary = ''
    while num > 0:
        binary = str(num % 2) + binary
        num = num // 2
    return binary
print(make_binary(15))

answered Feb 16 '22 at 13:54

Parvesh Kumar

1,104
7
16

It can also be done using bit shift and bitwise comparison: `binary = str(num & 1) + binary` and `num = num >> 1` – Jenny Feb 16 '22 at 14:03

Python function that turns a number into binary

1 Answers1