Filter Lambda Function

Question

How do I filter out the letter in the set of words with lambda function?

For example:

I have to filter out every word containing letter "K".

["rabbit", "chuck", "Joe", "war", "rock", "docker"]
["chuck", "rock", "docker"]

I was told to provide the efforts:

list = ["rabbit", "chuck", "Joe", "war", "rock", "docker"]
print(list)
listfilter = list(filter(lambda x: (x == 'k'), lst))
print(listfilter)

You should show your efforts... your attempt and what the problem is you encounter. — trincot, Feb 26 '22 at 21:15

score 0 · Answer 1 · answered Feb 26 '22 at 21:19

0

Read about Python's filter function. Example:

words = ['rabbit', 'chuck', 'Joe', 'war', 'rock', 'docker']
filtered_out = list(filter(lambda item: 'k' not in item, words))  # filtered out
print(filtered_out)

answered Feb 26 '22 at 21:19

Dennis

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Using the `filter` function was not the problem. The problem was to supply a `lambda` that does the correct thing. – mkrieger1 Feb 26 '22 at 21:32

BrokenBenchmark · Accepted Answer · 2022-02-27T00:21:38.943

0

There are two issues with your code:

The list variable name shadows the list() builtin -- pick a different name for your original list instead.
Your lambda function isn't correct. Instead of lambda x: x == k, it should be lambda x: 'k' in x.

data = ["rabbit", "chuck", "Joe", "war", "rock", "docker"]
listfilter = list(filter(lambda x: ('k' in x), data))

# Prints ["chuck", "rock", "docker"]
print(listfilter)

edited Feb 27 '22 at 00:21

answered Feb 26 '22 at 21:25

BrokenBenchmark

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But the result I "believe" he is trying to achieve is: `["chuck", "rock", "docker"]` not `['rabbit', 'Joe', 'war']` – Seraph Feb 26 '22 at 23:04

Filter Lambda Function

2 Answers2