Base64 to decimal

Question

Playing around with conversions in base64 with Python but I have hit a roadblock with trying to convert b64 to decimal.

The following code is suggested on stackoverflow previously but doesn't seem to work for me.

I looked up the error and it appears that this means it can't decode b6 because it is already decoded...

b6 = 'FhY='
print(' '.join([ str(ord(c)) for c in b6.decode('base64') ]))

#expectedoutput = 22 22 
#'str' object has no attribute 'decode'

Did you mean to just use [`base64.b64decode(b6)`](https://docs.python.org/3/library/base64.html#base64.b64decode)? — Green Cloak Guy, Mar 01 '22 at 18:12
This is the answer: https://stackoverflow.com/questions/28583565/str-object-has-no-attribute-decode-python-3-error — D.L, Mar 01 '22 at 18:12

OneCricketeer · Answer 1 · 2022-03-01T19:38:14.110

0

Bytes objects have decode function. Strings do not. The leading b on the string matters.

b6 = b'FhY='

Then, decode('base64') is not correct and will return error saying the codec doesn't exist.

Here is what you need, which returns a joined string of two decimal values

>>> ' '.join(map(str, base64.decodebytes(b6)))
'22 22'

edited Mar 01 '22 at 19:38

answered Mar 01 '22 at 18:20

OneCricketeer

`ord(chr(c))` is a complicated way of saying `c`. – Sören Mar 01 '22 at 19:34
@Sören You're right. I was trying different things. Have updated – OneCricketeer Mar 01 '22 at 19:38

1 Answers1