What is wrong in this way of using PHP scandir() function?

Question

I have been writing a simple PHP script for reading all files in a directory and show them but it show Unknown files, my files in images folder just two images but scandir() returning to me 4 result that first is "." (point) and second is ".." (double point). these results are from where?

This is my PHP function :

    $carpet_images=scandir('./images');

    print_r($carpet_images);

and this is result:

Array
(
[0] => .
[1] => ..
[2] => 1562475195-1796949251.jpg
[3] => 5f931b6fdbbdc8bfbd164f4bb08334ec_zzz-1.jpg
)

In almost every example of scandir there is code to ignore the `.` and `..` directories — RiggsFolly, Mar 13 '22 at 11:46
No, I didn't looked dir or ls -a output in this case because I am using this script in a share host and I have not access to command line — Mohammad, Mar 13 '22 at 11:48
https://unix.stackexchange.com/questions/63081/what-are-and-directories — RiggsFolly, Mar 13 '22 at 11:49
_No, I didn't looked dir or ls -a output_ What? Never? On any system? Even Windows?? — RiggsFolly, Mar 13 '22 at 11:49

score 1 · Accepted Answer · answered Mar 13 '22 at 11:48

1

. is the current directory, .. is the parent directory. You can filter those out like this:

$directories = scandir("./images");

$carpet_images = array_filter($directories, function($var) {
    return !in_array($var, ['.', '..']);
});

answered Mar 13 '22 at 11:48

Lajos Arpad

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What is wrong in this way of using PHP scandir() function?

1 Answers1