Restrict string size and display the rest of the string in next line

Question

I'm working on a string formatting problem where I'm trying to display the string to the specified size. I need to split the string after 4 commas and display the string in the next line.

INPUT:

char *str = "0-2025,0-2024,0-2023,0-2022,0-2021,0-2020,0-2019,0-2018,0-2017,0-2016";

EXPECTED OUTPUT:

0-2025,0-2024,0-2023,0-2022
0-2021,0-2020,0-2019,0-2018
0-2017,0-2016

I'm trying to add a special character '*' so that I can tokenize and use if for display.

My approach and code is given below, but I'm facing some issue when special character is added at the end.

#include <stdio.h>
#include <string.h>
int nthChar(char *str, char ch, int N){
    int occur = 0;
    for (int i = 0; i < strlen(str); i++) {
        if (str[i] == ch) {
            occur += 1;
        }
        if (occur == N)
            return i;
    }
}
int main()
{
    char *str = "0-2025,0-2024,0-2023,0-2022,0-2021,0-2020,0-2019,0-2018,0-2017,0-2016,0-2015,0-2014,0-2013,0-2012,0-2011,0-2010";
    char ch = ',';
    int N = 4, res;
    
    res = nthChar(str,ch,N);
    printf("%d\n", res);
    
    char priority[128];
    strcpy(priority,str);
    int size=strlen(str);
    printf("size = %d\n",size);
    int d = size/res;
    printf("DIV =%d\n",d);
    printf("%s\n", priority);
    for(int i=0;i<strlen(str)&&res<strlen(str);i++){
        for(int j=1,k=0;j<=d,k<d;j++,k++){
            priority[res*j+k] = '*';
        }
        
    }
    printf("%s", priority);
    return 0;
}

Current Output :

27
size = 111
DIV =4
0-2025,0-2024,0-2023,0-2022,0-2021,0-2020,0-2019,0-2018,0-2017,0-2016,0-2015,0-2014,0-2013,0-2012,0-2011,0-2010
0-2025,0-2024,0-2023,0-2022*0-2021,0-2020,0-2019,0-2018*0-2017,0-2016,0-2015,0-2014*0-2013,0-2012,0-2011,0-2010*�O?��

you can use the inbuilt ```strtok()```function to split the string. refer here for the [reference](https://stackoverflow.com/questions/3889992/how-does-strtok-split-the-string-into-tokens-in-c) — gretal, Mar 16 '22 at 06:46
Please focus your question on the specific problems encountered while trying yourself. For that please show a [mre] of the best attempt, the closest you got. — Yunnosch, Mar 16 '22 at 07:29
Look at each character of your string, if it is a comma, increase a counter by one and if the counter reaches the number `4`, insert/print a newline, set the counter to `0` and continue looking. Alternatively use `strchr` (or `strcspn` for a more sophisticated search). — Erdal Küçük, Mar 16 '22 at 07:50

score 0 · Answer 1 · answered Mar 16 '22 at 08:05

you can create a function which will split with comma and then slice from 0 index to 4 index. With this you can create a div and append them anywhere. Here is the code:

const comaSplit = () => {
    const text = document.getElementById('main').innerText
    const array = text.split(',')
    let init = 0
    for (i = 0; i < array.length; i += 4) {
        const first = array.slice(init, (init + 4))
        const string = first.join(',')
        init = init + 4
        const div = document.createElement('div')
        div.innerText = string
        document.getElementById('root').appendChild(div)
    }
}
comaSplit()

score 0 · Accepted Answer · edited Mar 18 '22 at 15:05

#include <stdio.h>
#include <string.h>
int nthChar(char *str, char ch, int N){
    int occur = 0;
    for (int i = 0; i < strlen(str); i++) {
        if (str[i] == ch) {
            occur += 1;
        }
        if (occur == N)
            return i;
    }
}
int main()
{
    char *str = "0-2025,0-2024,0-2023,0-2022,0-2021,0-2020,0-2019,0-2018,0-2017,0-2016,0-2015,0-2014,0-2013,0-2012,0-2011,0-2010";
    char ch = ',';
    int N = 4, res;
    
    res = nthChar(str,ch,N);
    
    char priority[128];
    strcpy(priority,str);
    int size=strlen(str);
    //printf("size = %d\n",size);
    int d = size/res;
    //printf("DIV =%d\n",d);
    //printf("%s\n", priority);
    for(int j=1,k=0;j<=d,k<d && res<strlen(str);j++,k++){
        if((res*j+k)==size){
            //printf("End of the string check\n");
            priority[res*j+k] = '\0';
            
        }else {
            //printf("index =%d\n",(res*j+k));
        priority[res*j+k] = '*';
        }
    }
    char* token = strtok(priority, "*");
    while (token != NULL) {
        printf("%s\n", token);
        token = strtok(NULL, "*");
    }
    return 0;
}

OUTPUT:

0-2025,0-2024,0-2023,0-2022
0-2021,0-2020,0-2019,0-2018
0-2017,0-2016,0-2015,0-2014
0-2013,0-2012,0-2011,0-2010

I've tried an approach to find nth comma and then replace that with a distinct special character to tokenize it later for display purpose.

By reading blogs and more about char array I understood that the last character of the string should be '\0' which is by default handled.

I've tried a approach of changing every 4th comma to a special character and then tokenizing with that to display the output.

I've answered only this question. I've verified the output as well and any reviewers are welcome to test this in their local machine. Why am I not able to post any answers and I'm revoked of my answering privilege. Please help me with this issue. Any help is appreciated. — Jayaram18, Jun 01 '22 at 15:39

Restrict string size and display the rest of the string in next line

2 Answers2