typescript type with call signature instantiation

Question

While reading TypeScript documentation I stumbled upon this:

type DescribableFunction = {
  description: string;
  (someArg: number): boolean;
};

function doSomething(fn: DescribableFunction) {
  console.log(fn.description + " returned " + fn(6));
}

How can I create and instance of DescribableFunction?

Am I wrong to think `Object.assign` would work pretty well? – kelsny Mar 16 '22 at 14:10 — kelsny, Mar 16 '22 at 14:10

Sapientisat · Answer 1 · 2022-03-16T13:17:04.610

Edit: here's the cleaner way: SO answer link

I don't see how you can do it without casting. I would create a separate function for creating the DescribableFunction:

function createDesirableFunction(description: string, func: (someArg: number) => boolean): DescribableFunction {
    const result = func;
    (result as DescribableFunction).description = description;
    return result as DescribableFunction;
}

Here it is in action: Typescript Playground

typescript type with call signature instantiation

1 Answers1