How can I convert a uint8_t array to a char array or string in C?
uint8_t array[10];
Asked
Active
Viewed 1,460 times
-1
-
string and char array are two different things. – OldProgrammer Mar 18 '22 at 17:31
-
Show some more code and tell us what you want to do with the char array or string once "converted". – Jabberwocky Mar 18 '22 at 17:32
-
`uint8_t` is a `typedef` alias for `unsigned char`, no "conversion" is necessary; it is a matter of interpretation. In C a string is not a data-type. It is a sequence of characters terminated with `'\0'`. A `char` array is a "container" that can hold a string. In short, your question is ambiguous. What are you trying to achieve? – Clifford Mar 18 '22 at 20:19
1 Answers
0
You just have to cast it, assuming you system defines char as 8 bits:
char *string = (char*)array;
SGeorgiades
- 1,771
- 1
- 11
- 11
-
-
Given that a) `char` is an implementation's smallest data type, b) `char` must be _at least_ 8 bits, and c) the implementation defines `uint8_t`; it is implicit that in this case `char` is 8 bits. – Clifford Mar 18 '22 at 20:26