alternative control block in php doesn't work

Question

I have this code in my html file which is rendered by PHP:

<div>
  <?php if($SESSION.userName=='UNSET'):  ?>
     User is not logged in
  <?php else: ?>
     user is logged in: user name is: {{ @SESSION.userName }}
  <?php endif; ?>
</div>
<div> test  {{ @SESSION.userName }} 
</div>

The above code generates this output:

User is not logged in user is logged in: user name is: a
test a

This apparently means that the if statement is not calculated.

What is the problem and how I can fix it? I am new to PHP (just started today!)

Note: logged username is a

Edit1

The page is rendered using this function from an index.php file:

$f3->route(
  'GET @home:/',
  function ($f3) {
    $f3->set('html_title', 'MyServer');
    $f3->set('content', 'index.html');
    echo Template::instance()->render('layout.php');
  }

Your ```$SESSION``` should be ```$_SESSION```. And should be ```$_SESSION['userName']``` — Ibrahim Hammed, Mar 19 '22 at 11:44
I can see that $SESSION.userName output so it should be running. — mans, Mar 19 '22 at 11:45
@KIKOSoftware Yes, it gave me a big list of information, the PHP version is 7.4.28. I am using a server that I am sure that PHP is inststalled and configured on it. — mans, Mar 19 '22 at 11:51
Ah, well, normally you would need to use the php extension for PHP files. — KIKO Software, Mar 19 '22 at 11:52
I understand, but just try to change the extension from .html to .php and see if that helps... it probably will. Only .php files are scanned for embedded PHP code (normally). — KIKO Software, Mar 19 '22 at 11:56
Let me check whether the syntax you used, which is rather obscure, is still valid in PHP 7.4.28. — KIKO Software, Mar 19 '22 at 12:01
@KIKOSoftware This document says that it is valid: https://www.php.net/control-structures.alternative-syntax — mans, Mar 19 '22 at 12:02
Sorry, I ran out of ideas. PHP works, you use the .php extension, and your syntax is valid. You could still check the PHP logs, to see if anything is there, but I doubt it. — KIKO Software, Mar 19 '22 at 12:05
You're mixing up PHP code with some templating language understood by `Template::instance()->render()`. The parts that *are* working are the non-PHP parts like `{{ @SESSION.userName }}`. You need to look up the proper syntax for if statements in that templating language, not native PHP. — IMSoP, Mar 19 '22 at 12:24
I have something like that on my site but it uses `if (!isset($_SESSION['username'])) {` then redirect user back to index.php if they are not logged in — Emma Marshall, Mar 19 '22 at 12:26
@IMSoP I am using F3 library for templating and other tasks. — mans, Mar 19 '22 at 19:20
Then you need to learn the syntax it uses for if statements, not mix in PHP. — IMSoP, Mar 19 '22 at 19:21

score 1 · Accepted Answer · answered Mar 20 '22 at 03:41

As you mentioned you are using f3 template engine, according to its documentation you can use this for your condition:

<check if="{{ @SESSION.userName=='UNSET' }}">
    <true>
        <div>User is not logged in</div>
    </true>
    <false>
        <div> user is logged in: user name is: {{ @SESSION.userName }}</div>
    </false>
</check>

alternative control block in php doesn't work

Edit1

1 Answers1