How to wait pymongo find() results without looping all rows?

Question

Not getting any result in pymongo by find() function in my collection:

But if I loop that variable, then it loads:

The only thing I did is adding a loop (see line ):

    for row in local_data:
        print(row)

So if I put that loop it will load all rows and I will see retrieved: 46

How can I wait it to return results without looping like that? Something like mycollection.find().Wait()

See https://stackoverflow.com/questions/28968660/how-to-convert-a-pymongo-cursor-cursor-into-a-dict/28970776. — Manfred, Mar 19 '22 at 16:44
I can't share the code, but it's a simple mongodb.collection.find() instruction like any other — kuhi, Mar 19 '22 at 16:46

score 1 · Accepted Answer · answered Mar 19 '22 at 18:29

1

.find() returns an iterable cursor. You have to iterate it (e.g. with a for loop) to get the results. If you don't iterate it, it doesn't do anything.

You can wrap the find in a list() command that will create a list of returned documents.

answered Mar 19 '22 at 18:29

Belly Buster

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How to wait pymongo find() results without looping all rows?

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