Is there a builtin way to log any exception?

Asked Mar 23 '22 at 15:18

Active Mar 23 '22 at 15:24

Viewed 21 times

I wrote a decorator to log any exception a function might throw.

import logging

def log_exception(func):
    def func_new(*args, **kwargs):
        try:
            return func(*args, **kwargs)
        except Exception as e:
            logging.error(str(e))
            raise e
    return func_new

It is used like this:

@log_exception
def divide(a, b):
    return a/b

For example, divide(1, 0) would log 'division by zero'.

My question is whether there's a builtin or more robust way to achieve the same thing. Maybe in the logging or contextlib modules?

edited Mar 23 '22 at 15:24

asked Mar 23 '22 at 15:18

actual_panda

1,178
9
27

2

What is wrong with your decorator that you want to replace it? – Scott Hunter Mar 23 '22 at 15:20
1

@ScottHunter Would you recommend to implement `sum` in Python over using the builtin `sum`? I'm asking whether I reimplemented a feature I'm not aware of. – actual_panda Mar 23 '22 at 15:22
Probably a good question to ask *before* you write your own solution. – Scott Hunter Mar 23 '22 at 15:25
Does this answer your question? [Using python's logging module to log all exceptions and errors](https://stackoverflow.com/q/8050775/6045800) – Tomerikoo Mar 23 '22 at 15:26
@ScottHunter it's just a handful of lines to show what I want, it took a minute – actual_panda Mar 23 '22 at 15:26
1

"Maybe in the logging or contextlib modules?" Well, did you try reading the documentation for those modules? Or the [logging module cookbook](https://docs.python.org/3/howto/logging-cookbook.html#logging-cookbook)? – Karl Knechtel Mar 23 '22 at 15:27
The duplicate is about logging all uncaught exceptions, I want to limit this to specific functions – actual_panda Mar 23 '22 at 15:31
@Tomerikoo this is close, but I want to limit the solution to specific functions – actual_panda Mar 23 '22 at 15:34
So use a decorator... – Tomerikoo Mar 23 '22 at 16:51

Is there a builtin way to log any exception?

0 Answers0