#include<stdio.h>
int main(){
int i;
// printf("%d",sizeof(i)) ;
printf("%d",(sizeof(i) > (-1))) ;
return 0;}
why does the code print 0 when sizeof(i) gives 4 in 64 bit OS? why does (sizeof(i) > (-1))) gives false(0) ?
#include<stdio.h>
int main(){
int i;
// printf("%d",sizeof(i)) ;
printf("%d",(sizeof(i) > (-1))) ;
return 0;}
why does the code print 0 when sizeof(i) gives 4 in 64 bit OS? why does (sizeof(i) > (-1))) gives false(0) ?
Use a better compiler and enable warnings. Under any sane compiler you should have gotten a warning about comparing an unsigned and a signed value.
This should be closer to what you want:
printf("%d", (int)sizeof(i) > -1);
Or at least this:
printf("%d", sizeof(i) >= 0);
However your code is a no-op anyway, because it's impossible to have a negative size of a type.