1

I got error in encoding my inMemory User password using BCryptPasswordEncoder

here is my springsecurityconfig file

SpringSecurityConfig class

import org.springframework.security.config.annotation.authentication.builders.AuthenticationManagerBuilder;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder;
import org.springframework.security.crypto.password.PasswordEncoder;

@Configuration
@EnableWebSecurity
public class SpringSecurityConfig extends WebSecurityConfigurerAdapter {

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
                .csrf().disable()
                .authorizeRequests()
                .anyRequest()
                .authenticated()
                .and()
                .httpBasic();
    }


    @Autowired
    public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
        auth.inMemoryAuthentication()
                .withUser("admin")
                .password(passwordEncoder().encode("password"))
                .roles("USER");
    }

    @Bean
    public PasswordEncoder passwordEncoder(){
        return new BCryptPasswordEncoder();
    }


}

How can i properly encode the password without getting bean creation error

ngTouthang
  • 61
  • 1
  • 10

2 Answers2

0

You can use a more component-based approach to do that since the WebSecurityConfigurerAdapter has been deprecated in 5.7.0-M2.

@Configuration
@EnableWebSecurity
public class SpringSecurityConfig {

    @Bean
    public SecurityFilterChain appSecurity(HttpSecurity http) throws Exception {
        http
                .csrf().disable()
                .authorizeRequests()
                .anyRequest()
                .authenticated()
                .and()
                .httpBasic();
        return http.build()
    }

    @Bean
    public UserDetailsService userDetailsService(PasswordEncoder encoder) {
        User admin = User.withUsername("admin")
            .password(encoder.encode("password"))
            .roles("USER").build();
        return new InMemoryUserDetailsManager(admin);
    }

    @Bean
    public PasswordEncoder passwordEncoder(){
        return new BCryptPasswordEncoder();
    }


}

This way, you have in-memory authentication by providing a InMemoryUserDetailsManager as the implementation of UserDetailsService, and this bean is dependent on the PasswordEncoder.

You can find more detail on the reference docs.

0

Create a separate configuration class and move passwordEncoder() method to it.

Example:

import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder;
import org.springframework.security.crypto.password.PasswordEncoder;

@Configuration
public class PasswordEncoderConfig {

    @Bean
    PasswordEncoder passwordEncoder() {
        return new BCryptPasswordEncoder();
    }

}

And then modify SpringSecurityConfig as below:

@Configuration
@EnableWebSecurity
public class SpringSecurityConfig extends WebSecurityConfigurerAdapter {

 @Autowired
 private PasswordEncoder passwordEncoder; //new line

 @Autowired
 public void configureGlobal(AuthenticationManagerBuilder authentication) throws Exception {
    authentication.inMemoryAuthentication()
      .withUser("admin")
      .password(passwordEncoder.encode("password")) //update line
      .roles("USER");
    }
}