How can I create a partial with named arguments supplied in a dictionary?

Asked Mar 29 '22 at 06:32

Active Mar 29 '22 at 06:32

Viewed 17 times

Say I have a lambda function foo:

foo = lambda x,y,z: return x + y + z

and a dictionary:

args = {"y":2, "z":3}

How do I create a partial with foo and args e.g.

my_partial = partial(foo, args)

such that I can call it with the one remaining argument?

my_partial(1) == 6

asked Mar 29 '22 at 06:32

dnb

Are you expecting to call `partial(foo, {"x": 1, "y": 3})`. Are you expecting the resulting partial function to take positional arguments, or either positional or keyword arguments? – Frank Yellin Mar 29 '22 at 06:36
`partial(foo, **args)`…‽ – deceze Mar 29 '22 at 06:41
A `lambda` can’t contain a `return` FWIW… – deceze Mar 29 '22 at 06:42

0 Answers0