Python can't remove a values index in a list when I am able to print the same value using its index

Question

I am trying to remove a value from the list but python seems to not be able to even though I am able to print it. The value is 5 which you will be able to see in the error but when I try to remove the same value it throws me an error message.

The "sequence.remove(e+1)" line should be the same value as "print(sequence[e+1])" right?

code:

def solution(sequence):
    decisionList = []
    ultDec = bool
    def comparing():
        i = 0
        decisionList.clear()
        for i in range(len(sequence)-1):
            num1 = i
            num2 = i + 1
            if sequence[num1] < sequence[num2]:
                decisionList.append("bigger")
            if sequence[num1] > sequence[num2]:
                decisionList.append("smaller")
            if sequence[num1] == sequence[num2]:
                decisionList.append("equal")
        findIrregular()
        
    repeated = 0
    
    def findIrregular():
        nonlocal repeated
        ultDec = ""
        e = 0
        for e in range(len(decisionList)):
            
            val1 = e
            
            if decisionList[val1] == "smaller":
                if repeated < 1:
                    print(sequence[e+1], "is the value im trying to remove")
                    sequence.remove(e+1)
                    repeated = repeated + 1
                    comparing()
                if repeated >= 1:
                    return False
                    
            elif decisionList[val1] == "equal":
                if repeated < 1:
                    sequence.remove(e + 1)
                    repeated = repeated + 1
                    comparing()
                if repeated >= 1:
                    return False
                    
            elif decisionList[val1] == "bigger":
                pass
            
        return True
    comparing()
    return findIrregular()
solution([3, 6, 5, 8, 10, 20, 15])

error: So as you can see "5 is the value im trying to remove" is what causes the error

5 is the value im trying to remove
Traceback (most recent call last):
  File "<string>", line 46, in <module>
File "<string>", line 44, in solution
  File "<string>", line 16, in comparing
  File "<string>", line 29, in findIrregular
ValueError: list.remove(x): x not in list

If the answer helped you then click on tick mark to accept it :) — Abhyuday Vaish, Apr 01 '22 at 11:22

score 2 · Answer 1 · answered Apr 01 '22 at 11:16

2

list.remove removes the given member of the list, for example, if we have a list like [1, 2, 5] and we use .remove(5) our list will be [1, 2]. If you want to remove a member by its index, try .pop(i)

answered Apr 01 '22 at 11:16

Erfan Saberi

134
8

You can use del too. – Erfan Saberi Apr 01 '22 at 11:17
https://stackoverflow.com/questions/11520492/difference-between-del-remove-and-pop-on-lists – Erfan Saberi Apr 01 '22 at 11:17

Ran A · Answer 2 · 2022-04-01T14:43:51.977

1

you can use

 sequence.remove(sequence[e+1])

or

 sequence.pop(e+1)

edited Apr 01 '22 at 14:43

answered Apr 01 '22 at 11:17

Ran A

746
3
7
19

score 1 · Answer 3 · answered Apr 01 '22 at 11:17

1

Well, remove takes the item/value you want to remove. If you want to remove by index then use .pop(index)

Instead of this:

sequence.remove(e+1)

Use:

sequence.pop(e+1)

answered Apr 01 '22 at 11:17

Abhyuday Vaish

2,357
5
11
27

Python can't remove a values index in a list when I am able to print the same value using its index

3 Answers3