I want to launch my VLC player through a Java program, can any one help me? Thanks in advance.
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1possible duplicate of [how to control VLC by java](http://stackoverflow.com/questions/3768397/how-to-control-vlc-by-java) – Steve-o Aug 24 '11 at 07:29
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Vlc is located on different places depending on your system, but this is for 64 bit
ProcessBuilder pb = new ProcessBuilder("C:\\Program Files (x86)\\VideoLAN\\VLC\\vlc.exe", "file to start with vlc");
Process start = pb.start();
and this should work for x86:
ProcessBuilder pb = new ProcessBuilder("C:\\Program Files\\VideoLAN\\VLC\\vlc.exe", "file to start with vlc");
Process start = pb.start();

Oskar Kjellin
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backslashes (\\) should be escaped: "C:\\Program Files\\VideoLAN\\VLC\\vlc.exe" – davorp Aug 24 '11 at 07:42
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ProcessBuilder pb = new ProcessBuilder("C://ProgramFiles/VideoLAN/VLC/vlc.exe", "D://avtar.mp4"); Process start = pb.start(); The Vlc player is opening for me but its not playing the video from the specified path. – ranganath.tm Aug 24 '11 at 07:46
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I am done with this problem the solution is something like this, you should paste the video file into yours workspace/yoursapplication/a.pm4 – ranganath.tm Aug 24 '11 at 10:05
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You might want to try this sample of code:
Runtime.getRuntime().exec("path_to_your_VLC_exe");
Unfortunately you will need to have an absolute path to your executable file, which sometimes cannot be obtained.
Look here for more examples: http://www.rgagnon.com/javadetails/java-0014.html

ŁukaszBachman
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public class Test {
public static void main(String[] args) throws IOException, InterruptedException {
Runtime.getRuntime().exec("\"E:\\Program Files\\VideoLAN\\VLC\\vlc.exe\"");
System.out.println("VLC started.");
}
}

davorp
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Usually, the first argument of any executable that works with files is the path of the file to open... for example: "vlc.exe MyVideo.mov" – davorp Sep 19 '12 at 17:39
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You'll need to specify an absolute path to the program, which might be a problem if you do not know where VLC is stored.

Dot NET
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