find element in dom, which has a second classname starting with certain letters with jquery

Question

I look for all links, which have a second classname, which starts with "_0". This classname works as a path for my internal use.

I tried the following queries with no success:

$('a.hint [class^=_0]') // hint is the name for the first class
$('a [class^=_0]')
$('a [class^=_0]')

Is there a short handy query to approach this?

JMax · Answer 1 · 2011-08-24T09:15:54.567

0

Try: $('a.hint[class^="_0"]') (with quotes surrounding the _0) as described in the jquery doc example

[EDIT] If one of your classes is not exactly hint then you shouldn't use a.hint

$('a.hint[class^="_0"]') look for a a tag containing the exact class name hint and one of the classes name begining with _0

What you are looking for is more probably: $('a[class^="_0"]')

You should show us your HTML code, that would really help!

edited Aug 24 '11 at 09:15

answered Aug 24 '11 at 08:38

JMax

@Andreas: indeed, i forgot to remove the space between `hint` and `[` as Richard pointed out in his answer - i've edited my answer – JMax Aug 24 '11 at 08:52

Richard Dalton · Answer 2 · 2011-08-24T08:49:29.457

0

You don't want a space after the a, also you could probably use the attribute contains selector instead:

$('a.hint[class*="_0"]')

edited Aug 24 '11 at 08:49

answered Aug 24 '11 at 08:39

Richard Dalton

that would find these letters in the middle of the classname as well – Andreas Aug 24 '11 at 08:50
Are you going to have those letters in the middle of a class name? Yes, you can check if it starts with 'hint _0' – Richard Dalton Aug 24 '11 at 08:54

score 0 · Answer 3 · answered Aug 24 '11 at 08:42

0

try this-

$('a.hint [class^="_0"]')

answered Aug 24 '11 at 08:42

Vivek

score 0 · Answer 4 · edited May 23 '17 at 12:19

0

If you are sure that its your second class then you can use $("a [class*=' _0']"). Please refer to this link this should help you. Using 'starts with' selector on individual class names

edited May 23 '17 at 12:19

Community

answered Aug 24 '11 at 08:44

Vins

4 Answers4