How do I map one letter to another in Python?

Question

I'm trying to map one letter to another in Python 3. But I'm getting the wrong output. Here's one of the test inputs:

txt = 'wlgp le scd wlgp'

output should be:

pick is the pick

But I'm getting this wrong output:

pick it tht pick

Here's my code:

def swapCharacters(txt):
    hash = {'c':'h', 'd':'e', 'e':'s', 'g':'c', 'l':'i', 'p':'k', 's':'t', 'w':'p'}

    for key in hash.keys():
        txt = txt.replace(key, hash[key])
    print(txt)

You get the wrong output because you keep on replacing values in the same string. E.g. `d` becomes `s`, and then `s` becomes `n` in a later replacement. Better approaches suggested [here](https://stackoverflow.com/questions/555705/character-translation-using-python-like-the-tr-command). — Robby Cornelissen, Apr 05 '22 at 03:49

score 1 · Accepted Answer · answered Apr 05 '22 at 04:10

If you are a fresher, you can do my easy way is getting each character in the string, check it in your mapping1 or not and return a suitable value, put it into a list, and use join to join the array by ''. I hope helpful to you

string = "".join([mapping1.get(c) if c in mapping1 else c for c in string])

How do I map one letter to another in Python?

1 Answers1