Why `a` can be printed from `baz`?

Asked Apr 06 '22 at 19:34

Active Apr 07 '22 at 00:15

Viewed 37 times

const Foo = function(a){

  // bar doesn't belong to any instance
  function bar(){
    console.log(a);
  };

  this.baz = function(){
    console.log(a);
  }
}

const f = new Foo(7);
f.baz() // print 7

Hi stackoverflows, can someone explain to me why f.baz() can print the a ?? Having difficulty explaining this to someone else right now

asked Apr 06 '22 at 19:34

Edward Sun

3

Well, it’s in scope. Why wouldn’t this work? – Sebastian Simon Apr 06 '22 at 19:36
What does `bar()` have to do with this? Why is it in the snippet? – Barmar Apr 06 '22 at 19:40
@SebastianSimon I still don't understand why it is in scope ?? can you tell me more on this – Edward Sun Apr 06 '22 at 23:55
@EdwardSun It’s in scope because it’s inside a function that has the parameter `a`. That’s how scope works in JS. It’s lexical scope. See the third linked Q&A. – Sebastian Simon Apr 07 '22 at 00:16

Why `a` can be printed from `baz`?

0 Answers0