How to crop an image based on its coordinates in Python Opencv

Question

I am drawing a cv2 rectangle by using below line

cv2.rectangle(rightImg, (x, y), (x + w, y + h), (0, 0, 255), 2)

Now values are

x = 93
y = 62
w = 6
h = 3

Now I want to crop that part of the rectangle. Does below line of code make sense:

cropImg = rightImg[y:x, y+h:x+w]

or

cropImg = rightImg[y+h:x+w, y:x]

I have tried both of the above but its not cropping the exact area. What can I try next?

Does this answer your question? [How to crop an image in OpenCV using Python](https://stackoverflow.com/questions/15589517/how-to-crop-an-image-in-opencv-using-python) — Christoph Rackwitz, Aug 28 '22 at 11:24
and please review [ask]. I would have expected any search at all to have turned up suitable answers. — Christoph Rackwitz, Aug 28 '22 at 11:26

Nishani Kasineshan · Answer 1 · 2022-08-16T15:57:59.133

1

you should try

cropImg=rightImg[y:y+h,x:x+w].

edited Aug 16 '22 at 15:57

answered May 31 '22 at 04:57

score 1 · Answer 2 · answered Aug 28 '22 at 09:53

1

crop_img = rightImg[y:y+h, x:x+w]
cv2.imshow("cropped", crop_img)
cv2.waitKey(0)

Be careful of marked as duplicates.

answered Aug 28 '22 at 09:53

asrulsibaoel

that is identical to an existing answer, with some superfluous fluff added – Christoph Rackwitz Nov 13 '22 at 20:26

score -1 · Answer 3 · answered Jul 23 '22 at 17:16

-1

It may look a bit weird but you have to write the y coordinates first.

cropImg = rightImg[y:y+h, x:x+w]

It will crop the image at where the rectangle is.

answered Jul 23 '22 at 17:16

Labib Ahmed

that is identical to an existing answer. – Christoph Rackwitz Aug 28 '22 at 11:24

3 Answers3