How do I remove a newline that is the last char in an array?

Question

So, I am trying to remove a newline that is the last char in an array. The issue is, that in earlier lines I need the newline break, so when I create the array, I leave it in there, so it looks like this:

fgets(input, 100, stdin);

char *array[10];
int i = 0;

array[i] = strtok(input, " ");

while(array[i] != NULL)
    array[++i] = strtok(NULL, " ");

but later on, when I run

execvp("echo", array);

It has an extra line break that I can't get rid of, like this (what it would look like from console):

(input) echo "hello"
(output) hello
(output)
*Continues code from here*

I am just wondering if anyone has any ideas on how I could remove the linebreak so, that when I run the execvp, there would not be an extra line?

@bobChicken It is enough to use the delimiter " \n" in calls of strtok. — Vlad from Moscow, Apr 13 '22 at 22:27

score 0 · Answer 1 · answered Apr 13 '22 at 22:35

0

This is the code snippet I use to remove the newline (before strtok).

fgets(in_line, LINE_LENGTH, stdin);
if ((strlen(in_line) > 0) && (in_line[strlen(in_line) -1] == '\n') )
    in_line[strlen(in_line)-1] = '\0';

answered Apr 13 '22 at 22:35

J27avier

121
4

[`buffer[strcspn(buffer, "\n")] = 0;`](https://stackoverflow.com/questions/2693776/removing-trailing-newline-character-from-fgets-input) Note, though, that will terminate the string on any newline. – Andrew Henle Apr 13 '22 at 23:22
J27avier, `strlen(in_line) > 0` better coded as `in_line[0] != 0`. – chux - Reinstate Monica Apr 14 '22 at 01:30

score 0 · Answer 2 · answered Apr 14 '22 at 01:38

0

To remove a newline that is the last char in an array

input[100-1] = 0;

To remove a newline at the end of a string fill by fgets()

input[strcspn(input, "\n")] = 0;

answered Apr 14 '22 at 01:38

chux - Reinstate Monica

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How do I remove a newline that is the last char in an array?

2 Answers2