Capturing output of asynchronous bash commands?

Question

Is it possible to do something like this in bash?

output=$(echo hello; sleep 10) &
pid=$!
# run some more commands
wait $pid
echo $output

I would like to run multiple commands in parallel, capturing their output. I'd like to do it in a "clean" way - not writing to temporary files etc.

probably try reading from the stdout files fd = 1 of the from `/proc//fd/1` — phoxis, Aug 25 '11 at 18:07

score 3 · Accepted Answer · answered Aug 25 '11 at 18:06

3

You can use a named pipe to communicate between parent and child, see man mkfifo for details. Parent can use read command to fetch data from the pipe.

answered Aug 25 '11 at 18:06

bobah

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There are some subtleties to how you collect the processes too, see https://stackoverflow.com/a/26240420/2492. – Sam Brightman Aug 02 '17 at 09:44

Capturing output of asynchronous bash commands?

1 Answers1