There is a struct and a generator function for it
template<int Size>
struct Foo
{
int buffer[Size];
};
template<int Size>
Foo<Size> generate(int Size)
{
return Foo<Size>();
}
and it produces this error:
: error: declaration of 'int Size' shadows template parameter
8 | Foo<Size> generate(int Size)
clearly, I can't use same name of integer template parameter as the function parameter to force it deduce the Foo template's parameter.
Is there a way to pick the template parameter like this:
auto foo = generate(32);
instead of this:
auto foo = generate<32>();
Here 32 is compile-time known so it could work if there was a way to do it and I don't expect it to work like this:
auto foo = generate(clock()); // not known, so won't work
On the other hand, it could be good if it could auto-generate it for a limited range like this:
auto foo = generate(clock()%10); // compile-time known to be between 0 and 9
because it is not possible to do it like this:
auto foo = generate<clock()%10>();
