How do I compare a list with an interger?

Question

This is what code I currently have (But in simplified form):

Example = [0, 0, 0, 0, 1]
Test = random.randint(0,len(Exmaple))
if Example[Test] == 1:
    print("Working")
else:
    print("Not Working")

I want it to print "Working" by detecting if it lands on the integer 1 I could do Example[4] but I want to change the amount of items there are in the list, so it would work if I changed Example to [0, 0, 0, 0, 0, 1]

Instead of choosing a random index, you can choose a random element directly: `if random.choice(Example) == Test` — DeepSpace, Apr 25 '22 at 11:50

score 0 · Answer 1 · edited Jun 01 '22 at 11:18

0

by changing if Example[Test] == 1: to random.choice(Example) == 1: it allows the code to print "Working" if it detects the interger 1

DeepSpace answered this in an comment:

Instead of choosing a random index, you can choose a random element directly: if random.choice(Example) == Test

edited Jun 01 '22 at 11:18

Nimantha

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answered Apr 25 '22 at 11:57

StinkingMerm

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How do I compare a list with an interger?

1 Answers1