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I have a datetime.datetime object that gets stored as text in a text file. Later, I have to convert that text back to a datetime.datetime object. The object is in this format 2022-04-18T10:00:00-07:00 but I'm having trouble using the strp time function to convert the text back. I tried running date_time_obj = datetime.strptime(timedatestamp, '%y-%m-%dT%H:%M:%S%z') but that format doesn't work because the time data is formatted wrong. Any clue as to what I'm doing wrong?

FObersteiner
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Duaa Zaheer
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  • It's `%Y` for a four-digit year, not %y. Or use datetime 's `fromisoformat`. – FObersteiner Apr 26 '22 at 06:22
  • Does this answer your question? [How do I parse an ISO 8601-formatted date?](https://stackoverflow.com/questions/127803/how-do-i-parse-an-iso-8601-formatted-date) – FObersteiner Apr 26 '22 at 06:23

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