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I have a code with a loop that I need to skip an iteration if it is taking too much time.

Example:

list = ['a', 'b', 'c', ......]

for x in list:

    #do something that takes time

In my code, the list has several paths. I loop through every path of that list to do some actions in files, but there are some files that take too long. I don't want the script to be stuck in a path for more than half an hour... If it takes more than 30 minutes while executing it, I want it to skip that path and go to the next on the list.

Catarina Ribeiro
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  • Please elaborate your requirement. The `list` has something when processed, takes more time? – Rohit Babu Apr 27 '22 at 11:09
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    Does this answer your question? [Timeout on a function call](https://stackoverflow.com/questions/492519/timeout-on-a-function-call) – matszwecja Apr 27 '22 at 11:09
  • @Rohit Babu, it's just a list with Paths. I loop through every path of that list to do some actions in files, but there are some files that take too long. I don't want the scrip to be stuck in a path for more than half an hour... If it takes more than 30 minutes, I want it to skip that path and go to the next. – Catarina Ribeiro Apr 27 '22 at 14:33

3 Answers3

1

I assume you mean that you want to break out of the loop if a certain amount of time has elapsed. If so, take a look at the time module. You can use features from there to note the time before you enter the loop then, at appropriate points in the code, compare the elapsed time from your initial record of the start time and continue accordingly

DarkKnight
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1

I've came up with this solution:


import time
start_time = time.time()

#a lot of code in the middle

print(start_time)

list=['1', '2', '3', '4']


for i in list:
    
    start_time = time.time()


    while True:

        print("hello world {}".format(i))

        current_time = time.time()
        elapsed_time = current_time - start_time

        print(elapsed_time)    

        if elapsed_time > 3: #test for 3seconds
            print("More than {} seconds".format(elapsed_time))
            del elapsed_time
            break
   
print("exited the loop")
Catarina Ribeiro
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-1

You might like this code

import pprint as p
llist = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
HashMap = {}
for i, x in enumerate(llist):
    HashMap[x] = i
    # Your condition
    if len(HashMap) > 20:
        break  # You can do continue 

p.pprint(HashMap, width = 200, sort_dicts = False)

Explanation

Imported pprint to print beautifully

changed the var name from list to llist because I don't want to mask built-ins

Created a dictionary HashMap to store the index of the items and the items

looped on llist using enumerate() to get those indices

After loop first step was to append the item to HashMap so that we keep the count

Then the condition will come.....

Then checking length of HashMap, if it exceed the condition then break

Finally to print it

Aadesh Gurav
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