Python selenium the problem with is_displayed()

Question

The purpose is I want to check the button is exist on web page and then click it, if not exist, just skip. But, it's not works if not 'is_displayed()', please suggest me how can I modify the code, thanks!

Here is the code:

button = wait.until(EC.element_to_be_clickable((By.XPATH, '//*[@id="ra_on"]')))
if button.is_displayed() == True:
    button.click()     #means turn to ON. It's works.

else:
    print('It's ON ready.')    #means turn ON ready. It's not works.

score 0 · Accepted Answer · answered May 04 '22 at 17:09

Use find_elements that will return a list of Web element, if found at least one Web element, if it does not find anything the list will be empty.

Code:

try:
    if len(driver.find_elements(By.XPATH, "//*[@id='ra_on']")) > 0:
        print("element must be displayed, do whatever you wanna do here")
        button = wait.until(EC.element_to_be_clickable((By.XPATH, "//*[@id='ra_on']")))
        button.click() 
    else:
        print("Element with xpath //*[@id='ra_on'] not found.")
except:
    print("Just skip it")
    pass

score 0 · Answer 2 · answered May 04 '22 at 22:59

To click on the button if it is clickable or else just to skip you can wrap up the line within a try-except{} block and you can use the following solution:

try:
    WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, '//*[@id="ra_on"]'))).click()
except TimeoutException:
    pass

Note: You have to add the following imports :

from selenium.common.exceptions import TimeoutException
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Python selenium the problem with is_displayed()

2 Answers2