Round number down to the next 1000 in python

Question

can somebody tell me how i can round down to the nearest thousand. So far I tried it with math.round(), the truncate function but i couldn't find my math skills to work out for me. As a example for some people I want that 4520 ends up in beeing 4000.

4000 is not the **nearest** thousand of 4520, this would be 5000 — mozway, May 06 '22 at 14:49

score 2 · Answer 1 · answered May 06 '22 at 14:49

2

In Python, you can do

print((number // 1000)*1000)

answered May 06 '22 at 14:49

Senthil

189
4
16

score 2 · Answer 2 · answered May 06 '22 at 14:49

2

just a thought

Why not do it the traditional way?!

deprecate_vals = 3 
val = 4520

val = int(val/(10**deprecate_vals)) * (10**deprecate_vals)
print(val)

answered May 06 '22 at 14:49

High-Octane

1,104
5
19

score 2 · Answer 3 · answered May 06 '22 at 14:50

You can divide by 1000 before rounding and then multiply by 1000.

invalue = 4320
outvalue = 1000 * round(invalue/1000)
print("invalue: ",invalue)
print("rounded value: ",outvalue)

output

invalue:  4320
rounded value:  4000

score 1 · Answer 4 · answered May 06 '22 at 14:49

There is multiple way to do it.

You can get the digit for the thousand by using the division (// mean without remaining, so you don't get 4,52 but 4)

x = 4520
rounded_x = (x//1000) * 1000

You can also use the remaining of the division with the modulo operator and remove it to the value :

x = 4520
rounded_x = x - (x%1000)

Round number down to the next 1000 in python

4 Answers4