I want to check the directory size:
• Low if the directory uses less than 3 MB of disk space
• Medium if the directory uses more than 3 MB and less than 8 MB of disk space
• High if the directory uses equal to or more than 8 MB disk space
For example:
> ./size.sh /usr/bin
High
> ./size.sh /tmp
Low
Here is the code that I try even though the folder contains this directory I still cannot do it.
#!/bin/bash
dir="breakfast"
DIRSIZE=`du -h "$dir"`
a=3145728
b=8388608
if (DIRSIZE -le "$a"); then
echo "Low"
else if (DIRSIZE -gt "$a" && DIRSIZE -lt "$b")
echo "Medium"
else if (DIRSIZE -ge "$b")
echo "High"
fi
Output:
sh quota.sh
: not found:
du: cannot access 'breakfast'$'\r': No such file or directory
quota.sh: 9: Syntax error: word unexpected (expecting "then")