Flask App - Local Development Environment - changes not reflecting

Question

I have a Flask App that I am running locally and testing. Every time, I make a change in the Application code, the changes would reflect on the dev environment http://127.0.0.1:8000/ with a simple browser refresh.

Now, I have to terminate the Flask App Ctrl X + Ctrl C and then reboot / relaunch the App. I am using gunicorn to launch the Flask App.

Not sure what changed, but how do I configure the App such that the changes take effect on refresh?

I have the following line of code in init.py:

if __name__ == '__main__':
    run_simple('0.0.0.0', 80, app, use_reloader=True, use_debugger=True)

when running your app did you set debug = true? `app.run(debug=True)` — bro, May 12 '22 at 22:44
@bro I have `use_debugger=True` in run_simple. Please see the code in the post. — kms, May 13 '22 at 21:32
I find it uncommon to use `gunicorn` in development environment. — DarkSuniuM, May 24 '22 at 02:20

score 10 · Answer 1 · answered May 18 '22 at 17:13

Gunicorn has its own system to reload the worker process when the application code changes. You can use the --reload CLI flag to activate the auto-reloading dev mode.

gunicorn --reload app:app

You can add additional files to the watcher via the --reload-extra-file FILES arg.

score 0 · Answer 2 · answered May 23 '22 at 21:02

0

Try

if __name__ == '__main__':   
    app.run(debug=True)

Also using Gunicorn

web: gunicorn wsgi:app

answered May 23 '22 at 21:02

Otu William

21
6

Flask App - Local Development Environment - changes not reflecting

2 Answers2