Math.ceil for positive value greater than zero?

Question

The following code is giving me a wrong answer and I can't understand why.

int x = 10;
int y = 15;
        
System.out.println((int)Math.ceil(x/y));

Result:

I was expecting a 1 as the answer.

You're dividing two integers, so you get integer division. 10/15 -> 0 — General Grievance, May 13 '22 at 18:55

score 0 · Answer 1 · answered May 13 '22 at 18:56

0

Inside the Math.ceil function you passed x / y and the answer of x / y in your case is gonna be 0 cause x and y are both integers and in Java, dividing two integers is going to give an integer result, thus 10 / 15 = 0 without taking the decimal digits. You can try defining x or y as double. Then you will get 10 / 15 = 0.666... and the ceil will return a 1.

answered May 13 '22 at 18:56

salam

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Please do not add answers to duplicate questions. – Gareth Ma May 13 '22 at 18:58

Math.ceil for positive value greater than zero?

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