How can I arrange a list of integers in python in txt file? Example = I am having:
['45 USD\n', '68 USD\n', '32 USD\n', '894 USD\n']
I want to arrange them in this order:
['894 USD\n', '68 USD\n', '45 USD\n', '32 USD\n']
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1How do you want to rearrange them, sorted by descending numbers in the strings? – Michael Butscher May 14 '22 at 10:07
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2This is a list of strings, not integers. Do you want to discard the non-number part and then sort them in descending order? – Piotr Siupa May 14 '22 at 10:08
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It would be better if you could explain the problem in more detail. – Circuit Planet May 14 '22 at 10:09
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do you also have any problem in getting these values from the txt file or is it just that you want to arrange them in the list. – Circuit Planet May 14 '22 at 10:17
2 Answers
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If all the strings in the list will have the same format, you could create a lambda function to sort them removing the "string" part and casting them to integers, as in:
L = ['45 USD\n', '68 USD\n', '32 USD\n', '894 USD\n']
print(sorted(L, key=lambda x: int(x[:-6]), reverse=True)) # x[:-6] removes the last 6 characters " USD\n"
result being:
['894 USD\n', '68 USD\n', '45 USD\n', '32 USD\n']
Shunya
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You should split x instead of using x[:-6] because the unit can be changed. – Circuit Planet May 14 '22 at 10:26
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We were not given an input like that, and I reiterate, this _particular solution_ works if all the strings in the list are expected to have the same format. – Shunya May 14 '22 at 10:33
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You can use the sort function for this.
a=['45 USD\n', '68 USD\n', '32 USD\n', '894 USD\n']
a.sort(reverse=True, key=lambda x: int(x.split()[0]))
print(a) # ['894 USD\n', '68 USD\n', '45 USD\n', '32 USD\n']
See this
Hope it helps ;)
Circuit Planet
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