Square Every Digit

Question

anyone could possibly help out why i've got such an error?

    def square_digits(num):
        result = [] 
        for x in num:
            result.append(x**2)
            return result
        pass

TypeError: 'int' object is not iterable

Thanks in advance

What are you sending `square_digits`? Is it possible you're sending an `int`? — Itai Dagan, May 18 '22 at 11:11
Can you provide some context? Maybe your ```num``` is not a list? — Kristof Rado, May 18 '22 at 11:11
Why do you have a return there in the loop, why do you have a pass after the loop, you cannot just iterate a number!? — luk2302, May 18 '22 at 11:11
Integer isnt a list. You need to separate out the digits mathematically — Suraj Rao, May 18 '22 at 11:11
% by 10 gives you a digit then you go // 10 to remove it, and you do this until you reach your desired one. Duplicate, flagging. — Josip Juros, May 18 '22 at 11:14

Kristof Rado · Answer 1 · 2022-05-18T11:22:46.150

0

Something like this should work. Convert the number to list of strings (digits of number) and iterate through this list.

Convert back to int when performing the square calculation (or convert to float if you are using non-int numbers)

    def square_digits(num):
        result = []
        nums = list(str(num))
        for x in nums:
            result.append(int(x)**2)
        return result

edited May 18 '22 at 11:22

answered May 18 '22 at 11:15

Kristof Rado

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Square Every Digit

1 Answers1