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We've got a base class for most of our domain object:

public class AbstractEntity<TKey>
{
    public virtual TKey ID { get; set; }
}

Now, for example, I've got class MobileOperator : AbstractEntity<int>.

What I want to do is to write generic equality comparer for all AbstractEntity descendants. And I want to create it like that:

var comparer = new AbstractEntityComparer<MobileOperator>();

I declare this comparer as following:

public class AbstractEntityEqualityComparer<TAbstractEntity, TId> : IEqualityComparer<TAbstractEntity>
    where TAbstractEntity : AbstractEntity<TId>

However, in this case I must explicitly tell the compiler that TId = int: new AbstractEntityComparer<MobileOperator, int>(). And if I put, say, long instead of int, it just wont compile. So, definitely, the compiler has a way to determine which type I use to create MobileOperator.

So is it possible to write comparer in a way that won't make me write this redundant int thing all the time? And if yes, how can I do it?

Qantas 94 Heavy
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HiveHicks
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  • No, that's not possible. See [here](http://stackoverflow.com/questions/7171067/no-type-inference-with-generic-extension-method/7171527#7171527). – Daniel Hilgarth Aug 29 '11 at 13:20

1 Answers1

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C# doesn't do type inference based on constraints, so you need the explicit generic construction. See the this blog post by Eric Lippert for the details (and also an argument in the comments about why he's wrong wrong wrong.)

dlev
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  • See also http://stackoverflow.com/questions/7179460/why-generic-extension-method-with-constraint-is-not-recognized-as-extension-metho/7179754#7179754 and http://stackoverflow.com/questions/7171067/no-type-inference-with-generic-extension-method/7171527#7171527 – Eric Lippert Aug 29 '11 at 15:11