how to use 'if i % number == 0:' with multiple numbers?

Question

just a quick question, how would i make it so that instead of just having 1 number (5 in this example) i could have multiple numbers (e.g. 5 or 6 or 7 etc.) or would i just have to do all of them seperately.

This is my example - if (i % 5 == 0):

i know it seems like a dumb question but i can't figure it out for some reason unless it's not possible. I've already tried if (i % 5 or 6 == 0): and if i % (5 or 6) == 0: but neither of them worked.

hope this makes sense thank you in advance

No, you have to do it separately, if by that you mean `(i % 5 == 0) or (i % 6 == 0)`. — mkrieger1, May 20 '22 at 19:29
Does this answer your question? [How to test multiple variables for equality against a single value?](https://stackoverflow.com/questions/15112125/how-to-test-multiple-variables-for-equality-against-a-single-value) — Sören, May 20 '22 at 19:29

inquirer · Answer 1 · 2022-05-21T10:40:33.523

1

You can use the 'mod' function from numpy, which will return the result as a list. And put the result in the any function, which will return True if at least one value has a remainder after division.

numpy.mod

import numpy as np

i = 10
aaa = np.any(np.mod(i, [1, 2, 3]))
print(aaa)

Output

True

Results the remainder is zero everywhere.

i = 10
aaa = np.any(np.mod(i, [1, 2, 5]))
print(aaa)

Output

False

edited May 21 '22 at 10:40

answered May 21 '22 at 10:26

inquirer

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how to use 'if i % number == 0:' with multiple numbers?

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