search for a name inside array that it's inside array

Question

I want to find a specific name given by user in this array if it's not found show a message. I tried but no result some help please.

<?php
$persons= array(
  array('name'=>'ADIANE','password'=>'adiane45'),
array('name'=>'ASABAN','password'=>'asaban23'),
array('name'=>'BENKASSOU','password'=>'benkassou67'),
);
?>

Your names all have a space at the beginning and end. Did you include that when you were matching against the input? — Barmar, May 22 '22 at 22:51
I have another question that says use function trim() to remove the space that's why. — feitan, May 22 '22 at 22:55
If you do `if ($input == trim($element['name']))` that should work. What did you do? — Barmar, May 22 '22 at 22:56
for what I tried it's all wrong I used 'for' and 'foreach' and 'array_key_exists' and 'in_array' the problem is how the get in the arrays that inside the main array to try if name = the name that we looking for — feitan, May 22 '22 at 23:00
I know about the trim() but first have to solve that one to pick the name that will apply trim() on it — feitan, May 22 '22 at 23:04
do I have to put all the wrong code that I tried and didn't work? — feitan, May 23 '22 at 14:02
See https://stackoverflow.com/questions/6661530/php-multidimensional-array-search-by-value — Barmar, May 23 '22 at 14:04
If it weren't wrong you wouldn't be here in the first place. But anyway, you can see the solution in the question I just linked to. — Barmar, May 23 '22 at 14:05

score 0 · Answer 1 · answered May 23 '22 at 03:59

0

Try this one, i hope this code will work:

$x = 0;
$pSize = count($persons);

foreach($my_array as $number => $number_array)
{
    $x++;
    foreach($number_array as $data = > $user_data)
        {
            print "Array number: $number, contains $data with $user_data.  <br>";
            if (trim($data) == $userInput)
            { 
                echo "Found";
                break;
            }elseif($pSize - $x == 0){
                echo "Not found";
            }

        }
}

answered May 23 '22 at 03:59

ali farhan

1
1

Your answer could be improved with additional supporting information. Please [edit] to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers [in the help center](/help/how-to-answer). – Community May 23 '22 at 08:25
What is `$my_array`? Shouldn't that be `$persons`? And why do you have a nested loop instead of just using `$number_array['name']`? – Barmar May 23 '22 at 13:46
And shouldn't `$data` be `$user_data`? – Barmar May 23 '22 at 13:46
Thank you with this code I'm able to find the specific name but if I tried to find the name and the password of it I can't. by using '&&' in the 'if' – feitan May 23 '22 at 13:55
$x = 0; $pSize = count($persons); foreach($persons as $number => $number_array){ $x++; foreach($number_array as $data => $user_data){ if ($user_data == trim($nameInput) && $passInput == $user_data) { echo "Bienvenue Monsieur $nameInput"; break; }elseif($pSize - $x == 0){ echo "Votre login et/ou mot de passe n'est pas reconnu."; break; } } }}` – feitan May 23 '22 at 13:58
this is the code that I used – feitan May 23 '22 at 13:58

score 0 · Accepted Answer · answered May 24 '22 at 19:22

this is the answer thank you all for help.

$nameInput = $_POST['name']; $passInput = $_POST['password'];

        $nameInput = strtoupper($nameInput);
        $c=0;
        foreach($persons as $key) {
            if($key['name'] == trim($nameInput) && $key['password'] == $passInput){
                $c+=1;
                break;
            }
        }
        if ($c==1){
            echo "Bienvenue Monsieur $nameInput ";
        }else{
            echo "Votre login et/ou mot de passe n'est pas reconnu.";
        }

search for a name inside array that it's inside array

2 Answers2