Regex different hashes

Question

so I'm struggling with regex. I'll start with what I want to achieve and then proceed to what I have "so far".

So for example I have commit name lines

merge(#2137): done something
Merge pull request #420 from Example/branch
feat(): done something [#2137JDN]
merge(#690): feat(): done something [#2137JDN]

And I want to grep only by PR ID, or if it's not there then it'd search by that second hash

#2137
#420
#2137JDN
#690

For now I have this regex, but it's not perfect

/(\(|\s|\[)(#\d+|#.+)(\)|\s|\])/g

because it's capturing this

(#2137)
\s#420\s
[#2137JDN]
(#690)[#2137JDN]

How I can improve it to get what I want exactly?

What about `(?<=[(\s[])#[^\])\s]+`? See https://regex101.com/r/w9UxHj/1 — Wiktor Stribiżew, May 23 '22 at 16:15
@MohammadRifatArefin for now I didn't decide in which language I want to write down the script. For now I'm testing solution of regex on https://regexr.com/ — TheTanadu, May 23 '22 at 16:56
@WiktorStribiżew hmm, it's using positive lookbehind and it's a little bit more complicated than answer below, but yes it's working. — TheTanadu, May 23 '22 at 16:57
But it can be just [`#\w+`](https://regex101.com/r/w9UxHj/2), too. It depends on the logic you actually need to implement. — Wiktor Stribiżew, May 23 '22 at 16:58

score 1 · Accepted Answer · answered May 23 '22 at 16:30

1

You can use the #[\dA-Z]+ pattern to grep only hashes.

command | grep -Po "#[\dA-Z]+"

Which returns the all matched strings (in our case - hashes)

#2137
#420
#2137JDN
#690
#2137JDN

Unfortunately, grep does not support non-greedy feature. See this answer.

answered May 23 '22 at 16:30

Artyom Vancyan

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Oh thanks! I mean I didn't decided yet in which script language (or tool like `grep`) I'll use it, I'm just testing logical prove of concept. But seems great. I can each line "compare" to the regex and by that `/(#[\da-zA-Z]+){1}/s` sounds reasonable for what I want to achieve (to get always FIRST match). – TheTanadu May 23 '22 at 17:00

Regex different hashes

1 Answers1