Create a list with string + range

Question

I need your help:

I want to create a list looking like this ['Unnamed: 16', 'Unnamed: 17', 'Unnamed:18'] for a range (16,60). How can I proceed?

I don't know if my question is clear but it's like doing list(range(16, 60) but with a string before each numbers.

Thank you very much for your help!!

First of all you didn’t format your code properly you have a missing bracket. Also don’t ask how to write code, see “How to ask Questions”. Instead show what you have tried. — Fishball Nooodles, May 25 '22 at 10:03
https://stackoverflow.com/questions/29339525/python-short-way-of-creating-a-sequential-list-with-a-prefix — Rabinzel, May 25 '22 at 10:03

score 3 · Accepted Answer · edited May 28 '22 at 18:26

3

You can use f-strings to do so :

my_list = [f"Unnamed: {i}" for i in range(16, 60)]

# Output
['Unnamed: 16', 'Unnamed: 17', 'Unnamed: 18', 'Unnamed: 19', ...]

edited May 28 '22 at 18:26

answered May 25 '22 at 10:02

Titouan L

score 0 · Answer 2 · answered May 25 '22 at 10:04

I would do it following way

prefix = "Unnamed: "
lst = [prefix + str(i) for i in range(16,25)]
print(lst)

output

['Unnamed: 16', 'Unnamed: 17', 'Unnamed: 18', 'Unnamed: 19', 'Unnamed: 20', 'Unnamed: 21', 'Unnamed: 22', 'Unnamed: 23', 'Unnamed: 24']

Note: I used othre range for brevity sake. You might elect to use one of string formatting method instead.

score 0 · Answer 3 · answered May 25 '22 at 10:09

0

You can do it using map as,

list(map(lambda x: f'Unnamed: {x}', range(16, 60)))

answered May 25 '22 at 10:09

score 0 · Answer 4 · answered May 25 '22 at 10:14

0

You can use f strings

name = 'Unamed:'
list = [f"{prefix} {i}" for i in range(16, 60)]
print(list)

answered May 25 '22 at 10:14

Kermit

Pavan Subhakar · Answer 5 · 2022-05-26T04:56:46.830

-1

my_list = []

for i in range(16, 60):

    my_list.append("Unnamed: " + str(i))

print(my_list)

edited May 26 '22 at 04:56

answered May 25 '22 at 10:36

Pavan Subhakar

1

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5 Answers5